X=6 is the answer to your question
Answer:
-4320t^2
Step-by-step explanation:
Use Pascal's triangle to figure out the variables.
In the 5th expansion, we see that the 4th term is:
10x^2 y^3
Plug in the values,
10*(4)^2 * (-3)^3 = -4230.
However, since the -3 in the original expression does not have a variable next to it, we do not include it in our answer.
Therefore, the 4th term is -4230t^2
Answer:
B
broh the answer is b broh
Answer:
285,753 cm³/min
Step-by-step explanation:
The rate of change of volume is the product of the water's surface area and its rate of change of depth.
At a depth of 2 m, the water has filled 1/3 of the 6 m depth of the tank. So, the radius at the water's surface will be 1/3 of the tank's radius of 2 m. The water's surface area is ...
A = πr² = π(2/3 m)² = 4π/9 m²
The rate of change of depth is 0.2 m/min, so the volume of water is increasing at the rate ...
dV/dt = (0.20 m/min)(4π/9 m²) = 8π/90 m³/min ≈ 279253 cm³/min
This change in volume is the difference between the rate at which water is being pumped in and the rate at which it is leaking out:
2.8×10⁵ cm³/min = (input rate) - 6500 cm³/min
Adding 6500 cm³/min to the equation, we get ...
input rate ≈ 285,753 cm³/min
Answer:
f(-2) = 3
Step-by-step explanation:
f(x) = x² + 3x +5
f(-2)=(-2)² + 3*(-2)+5
= 4 - 6 +5
= 3
