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DerKrebs [107]
3 years ago
12

Find the derivative of the function

Mathematics
1 answer:
Sav [38]3 years ago
3 0

Hello from MrBillDoesMath!

Answer:

27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)


Discussion:

Let f(t) - 9 sqrt(t) sin(t), then


y' = f(x^3) * d(x^3)/dx  - f(sqrt(x)) * d(x^1/2)/dx

   = (9 sqrt(x^3)sin(x^3)) * 3x^2 -  (9 sqrt(x^1/2)sin(x^1/2)) * (1/2) x^-(1/2)

   = 27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)


Hope I didn't make a "bozo" error differentiating things!


Thank you,

MrB

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