<u>Answer</u>
<em>The total displacement of the object is 320 m</em>
<u>Solution-</u>
From the formulas of mechanics,

Where,
s = displacement
u = initial velocity = 0 ( ∵ As the body was in rest in the beginning )
t = time taken = 8 s
a = acceleration = -10 m/s² ( ∵ -ve is because of the downward motion)
Putting all the values,
( ∵ -ve displacement means it is in downwards)
Use substitution.
anywhere you see "a" , than you would plug in b + 2 in for it so....
(b - (b + 2)^4
now take the negative sign and distribute it "+"
so b - b is 0, than 0 - (-2) is -2.
so what is (-2)^4 ????? it would become positive 16
Answer:
29.42 units
Step-by-step explanation:
<u>1) Find the perimeter around the semi-circle</u>
To do this, we find the circumference of the circle using the given diameter:
where d is the diameter
Plug in 6 as the diameter

Divide the circumference by 2

Therefore, the perimeter around the semi-circle is 3π units.
<u>2) Find the perimeter around the rest of the shape</u>
Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.
Therefore, we add the following:
7+6+7
= 20
Therefore, the perimeter around that area of the shape is 20 units.
<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

Therefore, the perimeter of the shape is approximately 29.42 units.
I hope this helps!
Answer:
Step-by-step explanation:
40 X 4 = 7 X50
160miles = 350miles
It's completely correct to use the ' / ' sign for division.
Every fraction means division. It means
(the top number) divided by (the bottom number) .
These are easy to do on a calculator, and by now you should
also know how to do them with a pencil.
1). 5,320 / 61 = 87.213... (plus more decimal places)
2). 776 / 28 = 27.714... (plus more decimal places)
3). 1,624 / 23 = 70.608... (plus more decimal places)