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RSB [31]
3 years ago
6

2+2x=45 Solve for x 10 pts

Mathematics
2 answers:
velikii [3]3 years ago
5 0

Hello there!

Solve for x.

2+2x=45\\

Explanation:

↓↓↓↓↓↓↓↓↓↓↓

First you had to subtract by 2 from both sides of the equation.

2+2x-2=45-2

Simplify

2x=43

Then you divide by 2 from both sides of the equation.

\frac{2x}{2}=\frac{43}{2}

Simplify it should be the correct answer.

x=\frac{43}{2}

Answer⇒⇒⇒⇒⇒x=43/2

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

-Charlie

Volgvan3 years ago
3 0

2+2x=45

-2

0+2x = 43

2x = 43

-2

0+x=41

X=41

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P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
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19.49% probability that no more than 16 of them are strikes

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Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
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