The Cena can take 7 courses
We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.
<h3>What is the condition we can write here?</h3>
for solving this linear equation
First, subtract 35 from both sides.
isolate x so divide both sides by 22.50.
Therefore we get x = 6
Remember to add the additional class, so x is actually 7.
So,the Cena can take 7 courses.
To learn more about the linear equation visit:
brainly.com/question/1549055
Answer:
QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)
Step-by-step explanation:
The diagram is not shown, but we assume the points are in the sequence ...
P, Q, R, S, T
Since QR = RS, R is apparently the midpoint of QS, So ...
23. QR = 6/2 = 3
24. RS = QR = 3
25. PQ = QR = 3
26. ST = PT -PQ -QS = 20 -3 -6 = 11
27. RP = PQ +QR = 3 +3 = 6
28. RT = RS +ST = 3 +11 = 14
29. SP = PQ +QS = 3 +6 = 9
30. QT = QS +ST = 6 +11 = 17
Answer:
is there supposed to be a picture?
Step-by-step explanation:
Answer:
75 %
Step-by-step explanation:
To solve for the above question,
The percentage of pupils that submitted their project on time
= Number of pupils that submitted their project on time/Number of pupils × 100
Number of pupils that submitted their project on time = 30 pupils
Number of pupils = 40 pupils
= 30/40 × 100
= 75 %
The percent of the pupils that submitted their project on time is 75%
