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Vitek1552 [10]
3 years ago
9

What is an equation for the line that passes through the coordinates (4,5) and (8, 3)?

Mathematics
2 answers:
horsena [70]3 years ago
8 0
The equation to find the slope of a line is y2 - y1 / x2 - x1

So, what you do is take the y coordinate in your first point, which in this case is 5, and subtract it from your y coordinate in the second point, which is 3.

3 - 5 = -2
-2 / x2 - x1

Now take the x coordinate in your first point, which in this case is 4, and subtract it from the x coordinate in your second point, which is 8.

8 - 4 = 4

Now you're left with -2 / 4, which is the equation for the line that passes through the points (4,5) and (8,3)

Hope this helps!!
lapo4ka [179]3 years ago
4 0
-1/2x+7. Because x=(y2-y1)/(x2-x1)
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Answer: Mary has  16 video games.

Step-by-step explanation:

x+(x+2) =30

2x + 2 =30

       -2   -2

2x =28

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Answer:


Step-by-step explanation:

To find the least number of party favors, we have to consider the number of guests.


In this case, there are two possibilities—6 or 8.


For 6: 6, 12, 18, 24 (Add 6 to each number)

For 8: 8, 16, 24 (Add 8 to each number)


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7 0
2 years ago
Compare 7 x 103 and 2 x 103.
vekshin1
The answer is A) 7x103 is 3.5 times larger than 2x103
3 0
3 years ago
How do you figure out 3h = 120
cestrela7 [59]

Answer:

h=40

Step-by-step explanation:

3h = 120

Divide 3 on both sides of the equation.

\frac{3h}{3}=\frac{120}{3}

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5 0
2 years ago
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Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn
My name is Ann [436]
\bf c^2=a^2+b^2\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
------\\
a=m^2-n^2\\
b=2mn
\end{cases}\\\\\\ c^2=(m^2-n^2)^2+(\underline{2mn})^2
\\\\\\
c^2=m^4-2m^2n^2+n^4+\underline{2^2m^2n^2}
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c^2=m^4-2m^2n^2+n^4+{4m^2n^2}
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c^2=m^4+2m^2n^2+n^4\impliedby \textit{perfect square trinomial}
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c^2=(m^2+n^2)^2\implies c=\sqrt{(m^2+n^2)^2}\implies c=m^2+n^2
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3 years ago
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