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3 years ago

9

What is an equation for the line that passes through the coordinates (4,5) and (8, 3)?

2 answers:

horsena [70]3 years ago

8 0

The equation to find the slope of a line is y2 - y1 / x2 - x1

So, what you do is take the y coordinate in your first point, which in this case is 5, and subtract it from your y coordinate in the second point, which is 3.

3 - 5 = -2
-2 / x2 - x1

Now take the x coordinate in your first point, which in this case is 4, and subtract it from the x coordinate in your second point, which is 8.

8 - 4 = 4

Now you're left with -2 / 4, which is the equation for the line that passes through the points (4,5) and (8,3)

Hope this helps!!

lapo4ka [179]3 years ago

4 0

-1/2x+7. Because x=(y2-y1)/(x2-x1)

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If there is such a scalar function <em>f</em>, then

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$\implies\dfrac{\partial g}{\partial y}=4e^{4z}$

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Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

$f(x,y,z)=4xy^2+4ye^{4z}+h(z)$

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Integrate both sides with respect to <em>z</em> :

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