The exact values of the remaining <u>five</u> trigonometric functions of theta are
- sinθ = √3/2
- cosecθ = 2/√3
- cosθ = -1/2
- secθ = -2
- cotθ = -1/√3
Since tanθ = -√3.
The remaining <u>five</u> trigonometric functions of theta are sinθ, cosecθ, cosθ, secθ and cotθ.
The next trigonometric function of θ is cotθ.
cotθ = 1/tanθ
= 1/-√3
= -1/√3.
Also, tan²θ + 1 = sec²θ
Substituting tanθ = -√3 into the equation, we have
(-√3)² + 1 = sec²θ
3 + 1 = sec²θ
sec²θ = 4
secθ = ±√4
secθ = ±2
Since θ is in the quadrant II,
secθ = -2
Also, cosθ = 1/secθ
= 1/-2
= -1/2
Also, cot²θ + 1 = cosec²θ
Substituting cotθ = -1/√3 into the equation, we have
(-1/√3)² + 1 = cosec²θ
1/3 + 1 = cosec²θ
cosec²θ = 4/3
cosecθ = ±√(4/3)
cosecθ = ±2/√3
Since θ is in the quadrant II,
cosecθ = +2/√3
Also, sinθ = 1/cosecθ
= 1/2/√3
= √3/2
So, the exact values of the remaining <u>five</u> trigonometric functions of theta are
- sinθ = √3/2
- cosecθ = 2/√3
- cosθ = -1/2
- secθ = -2
- cotθ = -1/√3.
Learn more about trigonometric functions here:
brainly.com/question/4515552
Answer:
114.59155
Step-by-step explanation:
Answer:
290 centimetres
Step-by-step explanation:
The ratio of the length of the pieces of wood is 6 : 10 : 12.
We have to find the total ratio first:
6 + 10 + 12 = 28
The longer piece of wood has ratio 10.
The length of the original wooden plank is 812 centimetres, therefore, the length of the longer piece of wood is:
10/28 * 812 = 290 centimetres
Answer:
The function has a domain of all real numbers.
The function has a range of {y|–∞ < y <∞ }.
The function is a reflection of y=∛x
Step-by-step explanation:
Given:
f(x)=-∛x
domain is set of all values that x can take for which the function is defined, so
for above function domain= set of all real numbers
range is set of values that corresponds to the set of values of domain, so for given f(x) range={y|–∞ < y <∞ } set of real numbers
Now f(x)=-∛x hence its reflection will be
-f(x)=-(-∛x)
y=∛x !
2(z - 5) + (z - 8) =
= 2z - 10 + z - 8 =
= 2z + z - 10 - 8 = <u>3</u><u>z</u><u> </u><u>-</u><u> </u><u>1</u><u>8</u> ← the end
