Given the coordinates of the three vertices of a triangle ABC,
the centroid coordinates are (x1+x2+x3)/3, (y1+y2+y3)/3
<span>so (-4+2+0)/3=-2/3, ]2+4+(-2)]/3=4/3
so the coordinates are (-2/3, 4/3)</span>
I'm only going to alter the left hand side. The right side will stay the same the entire time
I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)
So with that in mind, this is how the steps would look:
tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x
Identity is confirmed
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:
Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer:
y = 7/5x + 4
Step-by-step explanation:
use the slope from the equation -5/7 and take the negative reciprocal to get the perpendicular slope = 7/5. Then use the equation y=mx+b. Plug in x and y from the point given and the new slope and solve for b.
(-3) = (7/5)(-5) + b, (-3) = -7 + b, add 7 to both sides. b = 4. Rewrite the equation now to be y = 7/5x + 4
Answer:
Step-by-step explanation:
Hello
Match the points on the number line with the rational numbers.
a __ -6/8 = -(2 x 3)/(2 x 4) = -3/4
b __ -2/8 = -2/(2 x 4) = -1/4
c __ -4/8 = -4/(4 x 2) = -1/2
d __ 8/8 = 1
e __ 13/8
