Question

write an equation in slope intercept form of the line that passes through (-1 5) and is parallel to the graph of 2y+4x= -8

Answer 1

Answer:

Therefore, equation of the line that passes through (-1,5) and is parallel to the line

$2y+4x=-8$  

is

$y=-2x+3$

Step-by-step explanation:

Given:

$2y+4x=-8$        .Equation of line

can be written as

$y=-2x-8$     ...which is in Slope intercept form

To Find:

Equation of line passing through ( -1, 5) and is parallel to the line 2y+4x=-8

Solution:

$y=-2x-8$ ...........Given

Comparing with,  

$y=mx+c$    ....general form in slope intercept

Where m =slope  

We get

$Slope = m = -2$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-1 , 5) will also have the slope = m = -2.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-5)=-2(x-(-1))=-2(x+1)\\\\y-5=-2x-2\\y=-2x+3......Equation\ of\ line$

Therefore, equation of the line that passes through (-1,5) and is parallel to the line

$2y+4x=-8$  

is

$y=-2x+3$