X3−3=x9+3 what the answer

) (4 pts) roulette is a game of chance that involves spinning a wheel that is divided into 38 segments. a metal ball is tossed i

salantis [7]

A) 1/2
b) green would show up very often

3 0

3 years ago

What should be done to both sides of the equation in order to solve w - 9 = 15? Add 15. Subtract 15. Add 9. Subtract 9.

tia_tia [17]

That would be add 9:-

w - 9 + 9 = 14 + 9

w + 0 = 23

w = 23

5 0

3 years ago

Brandon works at a small petting zoo with 8 animals. He was looking at some data showing the masses of the animals. Each animal

insens350 [35]

Answer:

OPtion B. Both the mean and median will increase, but the mean will increase by more than the median.

Explanation:

You should not need to do calculations to determine how buying the horse affects the mean and median.

Without the horse, there are 8 animals. When the data are ordered, the median is the average of the 4th and the 5th weights: (7 + 27)/2.

With the horse, there are 9 animals. The median will be the 5th weight: 27

Then, the median increases from (7 +27)/2 to 27.

What about the mean?

The horse's weight is well beyond the weight of the other 8 animals. The range increases from 160 - 2 = 158 to 900 - 2 = 898.

Then, when you calculate the mean inlcuding the weigth of the horse, there will be a high increase.

Thus, without further calculations, you can conclude that "B. Both the mean and median will increase, but the mean will increase by more than the median"

7 0

3 years ago

Read 2 more answers

What is the best estimate

Nutka1998 [239]

The answer is b or 20

8 0

3 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

1 year ago