In the diagram <br> What is m

I need help on this quick

Pachacha [2.7K]

Answer:

The hypotenuse to the nearest tenth is 8.1

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

Let a be the x leg and b be the y leg

a = 7 units

b= 4 units

7^2 + 4^2 = c^2

49+ 16 = c^2

65 = c^2

Take the square root of each side

sqrt(65) = sqrt(c^2)

8.062257748 =c

To the nearest tenth

8.1 =c

7 0

3 years ago

"sports discount" has uniforms for 68$. They are offering a 20% discount on each uniform, and a 7 percent sales tax will be appl

charle [14.2K]

Answer:

58.208 times 8 equals 465.664 rounded down to 465.66

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the area A of the polygon with the given vertices.

Natalija [7]

Answer:

A = 35 square units

Step-by-step explanation:

Formula to calculate the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the segment between A(2, 2) and B(9, 2) = $\sqrt{(9-2)^2+(2-2)^2}$

= 7 units

Length of the segment between B(9, 2) and C(9, -3) = $\sqrt{(9-9)^2+(2+3)^2}$

= 5 units

Length of the segment between C(9, -3) and D(2, -3) = $\sqrt{(9-2)^2+(-3+3)^2}$

= 7 units

Length of the segment between A(2, 2) and D(2, -3) = $\sqrt{(2-2)^2+(2+3)^2}$

= 5 units

Therefore, given polygon is a rectangle.

Area of the rectangle = length × width

= 7 × 5

= 35 square units

4 0

3 years ago

Please help if you can pic attatched

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Subtract row 3 from row 1:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]$

Subtract row 3 from 7 times row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]$

Divide row 3 by 17:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 2 of row 3 from row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 6 of row 2 from row 1:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

$C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]$

$C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]$

3 0

3 years ago

Find the angle measure.<br><br> PLEASE EXPLAIN I NEED TO SHOW MY WORK

oksian1 [2.3K]

Answer:

135

Step-by-step explanation:

Because the two vertical lines are parallel

that answer your question?

3 0

3 years ago

In the diagram What is m