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3 years ago

BRAINLIESTT!!!!!! PLEASE ANSWER ASAP

Mathematics

1 answer:

blsea [12.9K]3 years ago

8 0

It does represent a function. For every 1 added to the x... 3 is added to the y.

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FREE 100 POINTS JUST SAY “SHAMALAMAMOOMOO”

Arisa [49]

Answer:

SHAMALAMAMOOMOO :) :) :) :) :)

5 0

3 years ago

Read 2 more answers

a birthday cake at the bakery was $30 originally. During a sale, a discount of 28% was given. A further 15% discount was given t

V125BC [204]

Answer:

$18.36

Step-by-step explanation:

In this question, we have to find the cost of the cake for the customer who orders a month early.

We know that the original price of the cake is $30.

We also know that there was a 28% discount and a 15% discount added to the purchase.

Remember, You don't add discount percentages together, you discount the prices separately.

Solve:

First, apply the 28% discount.

30 · 0.28 = 8.40

30 - 8.40 = 21.60

Now apply the 15% discount to the new price.

21.60 · 0.15 = 3.24

21.60 - 3.24 = $18.36

They needed to pay $18.36 for the cake.

6 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

The total bill for breakfast was $81.30. The group of friends

mr_godi [17]

Answer:

$93.50

Step-by-step explanation:

81.30 x 1.15 = 93.50

6 0

3 years ago

Which number line shows the solution to<br> 1/4 X + 1 < 5

alex41 [277]

Answer:

I think it's the third one

Step-by-step explanation:

I've done this before, but try the 3rd one, if not then try the second one. it's been awhile since I've done this. I'm sorry if I'm wrong

5 0

3 years ago