Answer:
Your question is no completed
First one: If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV. It's an even function. The fourth graph represents it.
If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.
7.20+24.75=31.95
so 31.95 per student
31.95*350=11,182.50
This will cost the student body $11,182.50
Answer:
y = 7/5 x + 31
Step-by-step explanation:
To find the slope, we need to use the formula
m = (y2-y1)/(x2-x1)
m =(-4-17)/(5- -10)
= -21/(5+10)
= 21/15
Divide the top and bottom by 3.
= 7/5
The slope is 7/5.
Using the point slope form of the equation,
y-y1 = m(x-x1)
y-17 = 7/5 (x--10)
y-17 = 7/5(x+10)
Distribute the 7/5 ths.
y-17 = 7/5 x + 7/5*10
y-17 = 7/5 x +14
Add 17 to each side
y = 7/5 x + 14 + 17
y = 7/5 x + 31
This is in slope intercept form, with the slope being 7/5 and the y intercept of 31