S = ut + (1/2)a(t²) Subtract ut from both sides
(1/2)a(t²) = S - ut Multiply both sides by 2
a(t²) = 2s - 2ut Divide both sides by t²
a= 2s/t² - 2u/t
a= (2S - 2ut)/t²
Answer is C) but there should be parentheses around the term (2S-2ut)
The answer to the first part is D
Answer:
1) 270 degrees
2) pi/4 rad
Step-by-step explanation:
1.) For which value of theta is sine theta = negative 1?
Given
sintheta = -1
theta = arcsin(-1)
theta = -90degrees
Since sin is negative in the third and 4th quadrant
In the third quadrant, theta = 180 + 90 = 270degrees
In the fourth quadrant, theta = 360 - 90 = 270 degrees
Hence the required value of theta is 270degrees
2) Given the radius of the circle to be 1, the y axis value will also be 1 units
Opposite = 1
adjacent = 1
hyp = √1²+1²
hyp = √2
sin theta = opp/hyp
sin theta = 1/√2
theta = arccsin(1/√2)
theta = 45 degrees
Express in radians
45 degrees = pi/4 radians
Hence the required angle in the first quadrant is pi/4 rad
Answer:
6x+24
Step-by-step explanation:
just do distributing
