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never [62]
3 years ago
14

A deep sea diving bell is being lowered at a constant rate. After 12 minutes, the bell is at a depth of 600 ft. After 30 minutes

the bell is at a depth of 1900 ft. What is the average rate of lowering per minute? Round to the nearest hundredth as needed.
A. 72.22 ft per minute
B. 43.33 ft per minute
C.0.01 ft per minute
D. 63.33 ft per minute
Mathematics
2 answers:
timurjin [86]3 years ago
5 0

D. 63.33 ft per minute the deep diving bell

Masteriza [31]3 years ago
4 0

The answer is D i think

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weqwewe [10]
The answer is C. that is 67 percent of the original.
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3 years ago
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How do I find the zeros of x^4-10x^3-66x^2-94x-39
Gennadij [26K]

Answer: x = -1, -3, 7 + √62, 7 - √62


Step-by-step explanation:

q                                    p

x⁴ - 10x³ - 66x² - 94x - 39

\frac{p}{q} = +/- \frac{1*3*13*39}{1}

possible rational factors: 1, -1, 3, -3, 13, -13, 39, -39

Use synthetic division <em>or long division</em> to see which factor will leave a remainder of 0.

try x + 1 = 0  ⇒   x = -1

-1   |  1     -10     -66     -94     -39

    <u>|  ↓     -1        11        55      39 </u>

       1     -11      -55     -39       0

(x + 1)(x³ - 11x² - 55x - 39)        

next, try x + 3 = 0  ⇒   x = -3   <em>for the new polynomial</em>

-3   |  1     -11     -55     -39

     <u>|  ↓     -3       42     39</u>

        1     -14      -13       0  

(x + 1)(x + 3)(x² - 14x - 13)

Lastly: find the zeros by setting each factor equal to zero and solve.

x + 1 = 0  ⇒  x = -1

x + 3 = 0   ⇒ x = -3

x² - 14x - 13 = 0

x = \frac{-(b) +/- \sqrt{(b)^{2} -4(a)(c)}}{2(a)}

  = \frac{-(-14) +/- \sqrt{(-14)^{2} -4(1)(-13)}}{2(1)}

  = \frac{14 +/- \sqrt{196+52}}{2}

  = \frac{14 +/- \sqrt{248}}{2}

  = \frac{14 +/- 2\sqrt{62}}{2}

  = 7 +/- \sqrt{62}


5 0
3 years ago
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ehidna [41]

Answer:

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Step-by-step explanation:

The circumference = 12 * π

Rotating 3 times  the distance moved is 3 * 12π.

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