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3 years ago

HELP MEEEEEEE PLEASE

Mathematics

1 answer:

tresset_1 [31]3 years ago

7 0

The answer will be d

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Anybody know anything about special parallelograms? find y

MrRa [10]

Angle 1 is a right angle, so therefore:

3y-6 = 90

3y = 96

Y = 32

I hope this Helps!

7 0

4 years ago

Read 2 more answers

How do you make an exponential equation with these two points: (1,2) and (0.5,4)

Over [174]

The required equation is y=8×( $( \frac{1}{2} )^{x}$

Step-by-step explanation:

Given,

The two points are (1,2) and (0.5,4)

To find the exponential equation of these given points.

Formula

The general form of exponential equation is y = $ab^{x}$ where, A and B are any real number.

$\frac{x^{m} }{x^{n} } = x^{m-n}$

Now, the points satisfy the equation.

So,

2 = $ab^{1}$ ------- (1) and

4 = $ab^{0.5}$ ------ (2)

Now (1) ÷ (2) we get,

$\frac{ab }{ab^{0.5} }$ = $\frac{2}{4}$

or, $b^{0.5}$ = $\frac{1}{2}$

or, b = $\frac{1}{4}$ [ by squaring we get]

Now, from (1) we get,

2 = a× $\frac{1}{4}$

or, a = 8

Hence,

The equation is y=8×( $( \frac{1}{2} )^{x}$

4 0

3 years ago

HELP ME NOW PLEASE NOW ADGAFDKD;LHJ!!!!!! PLEASE AND THANK YOU :)))))

Eddi Din [679]

I got D.

There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:

1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator

1 - .1131 - .2005 = .6864

Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.