2 years ago

1 5/8 ÷ (−1 3/5)......plx help thx ....xd

Mathematics

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attashe74 [19]2 years ago

3 0

75/-104... .............

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Solve x'=5t(sqrt(x)) x(0)=1

LekaFEV [45]

Answer:

$2\sqrt{x}=\frac{5t^2}{2}+2$

Step-by-step explanation:

Given: $\frac{\mathrm{d} x}{\mathrm{d} t}=5t\sqrt{x}\,,\, x(0)=1$

Solution:

A differential equation is said to be separable if it can be written separately as functions of two variables.

Given equation is separable.

We can write this equation as follows:

$\frac{dx}{\sqrt{x}}=5t\,dt$

On integrating both sides, we get

$\int \frac{dx}{\sqrt{x}}=\int 5t\,dt$

Formulae Used:

$\int \frac{1}{\sqrt{x}}=2\sqrt{x}\,\,,\,\,\int t\,dt=\frac{t^2}{2}$

So, we get solution as $2\sqrt{x}=\frac{5t^2}{2}+C$

Applying condition: x(0) = 1, we get $C=2$

Therefore, $2\sqrt{x}=\frac{5t^2}{2}+2$

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The bag contained only red marbles and white marbles. If the ratio of red marbles to white marbles was

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Evaluate the derivative of the given function for the given value of x. Yequalsstartfraction 3 x minus 6 over 4 x plus 5 endfrac

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The area of a circle is 50.24 square inches. What is the circle's radius?

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