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Ainat [17]
3 years ago
14

Help please, I need to factorise this​

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

x={0,⅙}

Step-by-step explanation:

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Six time a number is greater then 20 more then that number
denpristay [2]
6n > n + 20. Hope it helps!
5 0
3 years ago
Solve for C and please show work
Zanzabum

Use the law of cosines:

c² = 8² + 11² - 2•8•11 cos(37°)

c² ≈ 44.4402

c ≈ 6.66634

4 0
3 years ago
Find the area of the surface. the part of the paraboloid z=4-x^2-y^2 that lies above the xy-plane
11Alexandr11 [23.1K]
Parameterize the surface (call it \mathcal S) by

\mathbf s(u,v)=\langle u\cos v,u\sin v,4-u^2\rangle

with 0\le u\le2 and 0\le v\le2\pi. Then the surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv

The area of \mathcal S is then given by the surface integral

\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv
=\displaystyle2\pi\int_{u=0}^{u=2}u\sqrt{1+4u^2}\,\mathrm du=\dfrac{(17^{3/2}-1)\pi}6\approx36.1769
6 0
3 years ago
PLRASE HELP ASAPPPPPPP​
garik1379 [7]
Answer: c. H

Explanation: 37+45+35+29+52=198
198/5=39.6

Hope this helped! :)
3 0
3 years ago
The weights of five grapefruits are 7 47 ounces, 7.23 ounces, 6.46 ounces, 7.48 ounces, and 6.81 ounces. Using the
gulaghasi [49]

Answer:

<u>The approximate total weight of the grapefruits, using the clustering estimation technique is B. 35 ounces.</u>

Step-by-step explanation:

We notice that the weights of the grapefruits given are slightly down or above 7, then we will use <em>7 as our cluster</em> for the estimation, as follows:

Weights

7.47 ⇒ 7

7.23  ⇒ 7

6.46  ⇒ 7

7.48  ⇒ 7

6.81  ⇒ 7

<u>Now we can add up 7 + 7 + 7 + 7 + 7 for the weights of the grapefruits and the approximate total weight is B. 35 ounces.</u>

8 0
3 years ago
Read 2 more answers
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