Given that m angle KLH=120^ which statement about the must be true? angle HLM is bisected by angle GLJ is bisected by vec LH . m
angle KLG=m angle HLJ m angle HLI=m angle LLM
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If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.
now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.
now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.
