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ollegr [7]
4 years ago
15

Which angles from a linear pair ?

Mathematics
1 answer:
densk [106]4 years ago
6 0
A pair of linear angles are formed by two intersecting line and add up to 180 degrees.
Hope this was helpful
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The base of the prism in the diagram is rectangular, but the edges that are not parallel to the base are tilted. What is the vol
Aneli [31]

Answer:

Volume of the prism is 648cm^3

Step-by-step explanation:

Given:

Base of the prism is rectangular in shape

Height of the prism = 6 cm

Base length of the prism= 12 cm

Base width of the prism= 9 cm

To Find:

Volume of the prism=?

Solution:

Volume of the prism ,

V= Base area of the prism x  Height of the prism

Here in the figure  base of the prism is in  Rectangular form

So the base area of the prism = area of the rectangle

We know that the area of the rectangle is = length x height

Substituting the values

Area of the Rectangle = 12 x 9

Area of the Rectangle = 108

So  the are of the base of the prism is  108cm^2

Now

Volume of the prism,

V= 108 X 6

V= 648cm^3

7 0
3 years ago
Fill in the table of values for y=x3+x2-6x
AfilCa [17]

Answer:

Step-by-step explanation:

y=5x-6x

y=(-1x)

6 0
3 years ago
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poizon [28]
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This is the attached diagram to 5
Ber [7]
The problem statement tells you ∠MLK is 61°, so ∠LMK = 180° -68° -61° = 51°. Since a tangent is always perpendicular to a radius, triangles LJM and LJK are right triangles.

Trigonometry tells you ...
  tangent = opposite / adjacent
so you can write two relations involving LJ.
  tan(51°) = LJ/JM
  tan(68°) = LJ/JK
The second equation can be used to write an expression for LJ that can be substituted into the first equation.
  LJ = JK*tan(68°) = 3*tan(68°)
Substituting, we have
  tan(51°) = 3*tan(68°)/JM
Multiplying by JM/tan(51°), we get
  JM = 3*tan(68°)/tan(51°)
  JM ≈ 6.01

The radius of circle M is about 6.01.

6 0
3 years ago
What is the slope of the linear function represented in<br> the table?<br> -7<br> -1/7<br> 1/7<br> 7
rewona [7]

Answer:

m=1/7

Step-by-step explanation:

Labeled the points and used Slope of a line formula.

7 0
3 years ago
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