Ask question

Ask question

All categories

3 years ago

13

Frederick is working on a number puzzle and discovers that the product of the two base numbers is exactly twice as large as the

sum of those same base numbers.
Help on this, please?

1 answer:

marishachu [46]3 years ago

6 0

To solve this problem, we are going to use trial and error.
If the 2 numbers are 3 and 4 then 3 and 4 is 12 and 3 + 4 = 7 which cannot be divided equally, so this is not the answer.
3 and 5 = 15 but this is not divisible by 2.
6 and 3 = 18 and 6 + 3 = 9 which is 1/2 of 18
therefore, one set is 6 and 3.

You might be interested in

Describing a Sequence of Transformations (8.1.A.6.3)

DedPeter [7]

Answer:

..

...................

4 0

3 years ago

Answer pls. <br> I'll give u brainliest if it's right

Bingel [31]

Answer:

The answer is C, (-5.-3)

Step-by-step explanation: brainliest please

3 0

4 years ago

Read 2 more answers

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

PERCENTS!! <br><br> due today help!!!! (:

kvv77 [185]

The answer is C. $144

6 0

3 years ago

Tate has 5 more than twice as many pennies as Mia. If Mia has x pennies, which equation can be used to find how many pennies she

sladkih [1.3K]

Answer:

3x + 5 = 30

Step-by-step explanation:

Tate has 2x + 5 pennies and since Tate and Mia have 30 pennies all together you would add an x to the equation of how many pennies Tate has and set it equal to 30 making the equation 3x + 5 = 30

7 0

3 years ago

Read 2 more answers