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suter [353]
4 years ago
10

PLEASE HELP ME WITH THIS will give brainly if you do please need help badly needs to be done in 20 mins (40 points)

Mathematics
1 answer:
Rudik [331]4 years ago
6 0

Answer:

1.A

2.E

3.E

4.B

5.C

6B

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After 7.5 years, you will have $3,200.12
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Plssss help in need of answers soon
vfiekz [6]
My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find.  It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A]  I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
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3 years ago
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And angle measures 54° more than the measure of its complementary angle what is the measure of each angle
Mashutka [201]
Answer:
The measure of the angles are 72 degrees and 18 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
Let
x -----> the measure of an angle
y-----> the measure of he other angle
we know that
x+y=90 -----> y=90-x -----> equation A
x=y+54 ----> equation B
substitute equation B in equation A and solve for y
y=90-(y+54)
y=90-y-54
2y=36
y=18°
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therefore
The measure of the angles are 72 degrees and 18 degrees
4 0
3 years ago
A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a ne
velikii [3]

Answer:

M = 1/0.000121 = 8264.5 years

Step-by-step explanation:

M = − k ∫∞₀ teᵏᵗdt

To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt

∫udv = uv - ∫ vdu

u = t

du/dt = 1

du = dt

∫ dv = ∫ eᵏᵗdt

v = eᵏᵗ/k

∫udv = ∫ teᵏᵗdt

uv = teᵏᵗ/k

∫ vdu = eᵏᵗ/k

∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k

But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²

∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²

The rest of the calculation is done on paper in the image attached to this question

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3 years ago
What is the quadric regression equation that fits these data
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Where’s the data?................
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