Use Pythagorean theorem.
a^2 + b^2 = c^2
D.
21^2 + 72^2 = 75^2
441 + 5184 = 5625
Hey there!
We can solve systems two ways - substitution and elimination. It seems in this case that elimination is going to be easier.
Let's begin by multiplying the top equation by 3, and the bottom equation by 4:
3(5x - 4y = -24)
15x - 12y = -72
4(4x + 3y = 18)
16x + 12y = 72
Next, we'll add the two equations together to get rid of, or eliminate, the y variable and solve for the x variable:
(15x - 12y = -72) + (16x + 12y = 72)
31x = 0
x = 0
Next, we'll plug the value of the x variable into the top equation and solve for the y variable:
5(0) - 4y = -24
-4y = -24
y = 6
Therefore, x = 0 and y = 6.
Hope this helps!! :)
The order of operations is PEMDAS. You would work on multiplying the -6 and 3.
Answer:
Step-by-step explanation:
#22
<h3>Given </h3>
- Equation x² -4x + 1 = k(x - 4) with equal roots
<h3>To find</h3>
<h3>Solution</h3>
<u>The equation in standard form is:</u>
- x² -4x + 1 = k(x - 4)
- x² - 4x - kx + 1 + 4 = 0
- x² - (k + 4)x + 5 = 0
<u>When the quadratic equation has equal roots its discriminant is zero</u>
- D = 0
- b² - 4ac = 0
- (k + 4)² - 4*5 = 0
- (k + 4)² = 20
- k + 4 = ± √20
- k = - 4 ± √20
- or
- k = -4 ± 2√5