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dezoksy [38]
3 years ago
14

Help me in this

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:    C)


Discussion:

To solve x^2 = 36/81  take the square root of both sides.

x = square root of (36/81)

As 36 = 6*6 and 81 = 9*9,

x = square root of (6*6)/ (9.9) or 6/9  

But 6 and 9 share the common factor "3" so

x =  6/9 = (2*3)/(3*3) = 2/3              

The last equality was gotten by cancelling the common factor 3.

         

Regards, MrB

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Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

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This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

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