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2 years ago

My last points to ask a question pls show work

Mathematics

2 answers:

BartSMP [9]2 years ago

6 0

Answer:

-9.5

Step-by-step explanation:

8.4×3=25.2

negative25.2- 5.7 equals negative 19.5 - 10. hey hi if my answer doesn't match with the answer in your book could you please tell me right away so that I can try another method or ask for help I would really like to help you bye.

const2013 [10]2 years ago

5 0

Answer:

14. 27

16. 170

Step-by-step explanation:

We must follow Order of Operations rules here. Work inside parentheses must be done first, then exponentiation, then multiplication and division, and finally addition and subtraction.

((5·7) - (8·4))³ becomes (35 - 32)³, or 3³, or 27.

16. 7² + ((46 - 7·2) + 2³)² becomes 7² + ((46 - 49) + 8)²

Again, do the work inside parentheses first:

7² + (3 + 8)² becomes 49 + 11², or 49 + 121, or, finally, 170

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One exterior angle of a regular polygon measures 97°. What is the measure of one interior angle?

3241004551 [841]

Hello :) = Merhaba :)

Answer:

Step-by-step explanation:

The total angle of a polygon and its external angle must be 180°.

So the inner angle of this polygon:

180 - 97 = 83° would.

NOTE: I'm not American. I'm just a Turk who wants to help you. So if my sentences are wrong, please forgive me.

<em><u>#Cevapistevereyim</u></em>

Başarılar :) = Achievements :)

4 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!