I need help please it’s due tomorrow.......

Mathematics

1 answer:

Sholpan [36]2 years ago

4 0

Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft

see the attached figure
the solution is<span> the shaded area</span>

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STatiana [176]

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For $f(x+\frac{5}{4})$ , $f(x)$ is translated $\frac{5}{4}$ units left.

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Step-by-step explanation:

The transformation of $f(x)\rightarrow f(x+C)$ means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of $f(x)\rightarrow f(x)+C$ means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of $f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0$ , so, the function translates left by $\frac{5}{4}$ units.

Similarly, in the transformation of $f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}$ , so, the function translates down by $\frac{5}{4}$ units.