Given : A = 24 sq feet
A = 0.5 base x height
base = x , height = x+2
A = 0.5 x(x+2) = 24 sq feet
1) 0.5 x(x+2) = 24 (A)
2) x^2 + 2x - 48 = 0 (D)
To check the rest un-wrap the bracket:
x^2 + (x+2)^2 = 24
x^2 + x^2 + 4 + 4x = 24
2x^2 + 4x - 20 = 0
x^2 + 2x - 10= 0 (NO)
Likewise:
x^2 + (x+2)^2 = 100
x^2 + x^2 +4 + 4x = 100
2x^2 + 4x + 4 = 100
2x^2 + 4x - 96 = 0
3) x^2 + 2x - 48 = 0 (F)
To sum up: that's what apply:
1) 0.5 x(x+2) = 24 (A)
2) x^2 + 2x - 48 = 0 (D)
3) x^2 + 2x - 48 = 0 (F)
Answer:
103.67 in³
Step-by-step explanation:
given Volume of cone is 1/3 * π * r² * h
here given r = 6/2 = 3 , height = 11 inch
using the formula = 1/3 * π * 3² * 11
=103.67 in³ or 33π in³
Answer:
2.5
Step-by-step explanation:
4*2.5= 10
8* 2.5=20
how i got 2.5 is by doing 10 divided by 4
< yvw and < twv are alternate interior angles
opposite sides of the transversal and inside are alternate interior angles
F(x) = 3(x-4)^2-38 because finding the perfect square would get you f(x)+38=3(x^2-8x+16) and then finding the squareroot of that and moving the constant on the left back to the right would leave u with f(x)=3(x-4)^2-38
