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andrew-mc [135]

3 years ago

6

Find the difference. Write your answer as a decimal. $5.5-8.1=$

2 answers:

Pie3 years ago

8 0

So you do 8.1-5.5= $2.60 :)

Tpy6a [65]3 years ago

4 0

Sorry I rlllllyyyyyyy don’t understanddddd

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Please help ASAP!!!!!!!!!

kondor19780726 [428]

Answer:

6.2

Step-by-step explanation:

Actual value: 6.15636257

7 0

3 years ago

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What are the factors of the expression (y-2)(x+3)

mr Goodwill [35]

The factors of the expression is 2and -3

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3 years ago

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Please help I will mark brainliest!!!!!!!!

Fiesta28 [93]

Answer:

I only know A

Step-by-step explanation:

A 37-9=28

I'm sorry I just have no idea what to do on the other ones xD

4 0

3 years ago

ellen sells mugs that are in boxes in a shape of a cube the edges have a length of 1/2 foot ellen can completely fill a containe

Yuri [45]

1/2 foot is 6 inches 6 times the amount of sides the cube has (6) would be 36 square inches so take that by the amount of boxes can fit(378) would give you the answer of 13,608

(p.s i am only in middle school i kind of understand this and i think this is right but if not i am 100% sorry)

5 0

3 years ago

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A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

7 0

4 years ago