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IgorC [24]
3 years ago
11

Please help me solve the equation3x+10y=487x+4y=54

Mathematics
2 answers:
agasfer [191]3 years ago
8 0
3x+10y=48
7x+4y=54


multiply the first equation by 2 and the 2nd equation by 5 to remove y
6x+20y=96
35x+20y=270
29x=174
x=6

substitute to any equation
7x+4y=54
42+4y=54
4y=12
y=3

the value of x is 6 and the value of y is 3
ser-zykov [4K]3 years ago
3 0

Answer: x=36/7

               y=9/2

Step-by-step explanation:

1 Solve for yy in 3+10y=483+10y=48.

y=\frac{9}{2}y=

​2

​

​9

​​

2 Substitute y=\frac{9}{2}y=

​2

​

​9

​​  into 7x+4y=547x+4y=54.

7x+18=547x+18=54

3 Solve for xx in 7x+18=547x+18=54.

x=\frac{36}{7}x=

​7

​

​36

​​

4 Therefore,

\begin{aligned}&x=\frac{36}{7}\\&y=\frac{9}{2}\end{aligned}

​

​

​​

​x=

​7

​

​36

​​

​y=

​2

​

​9

​​

​​

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*It depends what place value needs to be rounded down, but without any specific place values, here are my answers*

<em>600.1</em>

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6 0
3 years ago
Toni drives her car 99 mi on the highway on 3 gal of gas. At this rate how many miles can she drive on 11 gal of gas?
Helen [10]

Answer:

333.67 miles

Step-by-step explanation:

She drives her car 91 mi on 3 gal of gas

That’s 91 mi = 3 gal

How many miles can she drive on 11 gal of gas .

Let the mile she can drive by 11 gal of gas be A

At the same rate ,

91 mi = 3 gall

A mi = 11 gal

Cross multiply

A x 3 = 91 x 11

A x 3 = 1001

Divide both sides by 3

A x 3/3 = 1001/3

A = 333.67 miles

At the same rate she’ll drive 333.67 miles on 11 gal of gas

4 0
2 years ago
Is all parallelograms a square,why?
pychu [463]
No, all parallelograms are not squares because squares have to have all 90 degree angles, while parallelograms don't
6 0
3 years ago
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This is confusing I need help pls
DIA [1.3K]

The answer to your question is 42

4 0
3 years ago
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 + 4x + 8 = 0.
amid [387]

Answer:

The discriminant of ax^2+bx+c is b^2-4ac.  

If the discriminant, d, is:

d<0, there are no real solutions (there are two imaginary solutions however)

d=0, there is one real solution

d>0, there are two real solutions

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3 0
3 years ago
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