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IgorC [24]
3 years ago
11

Please help me solve the equation3x+10y=487x+4y=54

Mathematics
2 answers:
agasfer [191]3 years ago
8 0
3x+10y=48
7x+4y=54


multiply the first equation by 2 and the 2nd equation by 5 to remove y
6x+20y=96
35x+20y=270
29x=174
x=6

substitute to any equation
7x+4y=54
42+4y=54
4y=12
y=3

the value of x is 6 and the value of y is 3
ser-zykov [4K]3 years ago
3 0

Answer: x=36/7

               y=9/2

Step-by-step explanation:

1 Solve for yy in 3+10y=483+10y=48.

y=\frac{9}{2}y=

​2

​

​9

​​

2 Substitute y=\frac{9}{2}y=

​2

​

​9

​​  into 7x+4y=547x+4y=54.

7x+18=547x+18=54

3 Solve for xx in 7x+18=547x+18=54.

x=\frac{36}{7}x=

​7

​

​36

​​

4 Therefore,

\begin{aligned}&x=\frac{36}{7}\\&y=\frac{9}{2}\end{aligned}

​

​

​​

​x=

​7

​

​36

​​

​y=

​2

​

​9

​​

​​

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If x=10, write an expression in terms of x for the number 5,364
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Answer:

(5,354 + x)

or

536.4*x

Step-by-step explanation:

We know that x = 10.

Now we want to write an expression (in terms of x) for the number 5,364.

This could be really trivial, remember that x = 10.

Then:  (x - 10) = 0

And if we add zero to a number, the result is the same number, then if we add this to 5,364 the number does not change.

5,364 = 5,364 + (x - 10) = 5,364 + x - 10

5,364 = 5,354 + x

So (5,354 + x) is a expression for the number 5,364 in terms of x.

Of course, this is a really simple example, we could do a more complex case if we know that:

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And the product between any real number and 1 is the same number.

Then:

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