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Stels [109]
3 years ago
5

ᶜᵃⁿ ᵘ ᵖˡˢ ʰᵉˡᵖ ᵐᵉ ʷⁱᵗʰ ᵗʰᵉˢᵉ

Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer:

1) .136 is 13.6%

2) .371/2 is 37.5%, .081/3 is 8.3%, .045 is 4.5%

3) .0016 is .16%, .025 is 2.5%, .331/3 is 33.3%

4) .125 is 12.5%, .0375 is 3.75%

Step-by-step explanation:

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The area of a regular octagon is 35 cm^2. What is the area of a regular octagon with sides five times as long?
Marat540 [252]
So... let's say the smaller regular octagon has sides of "x" long, then the larger octagon will have sides of 5x.

\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}}
\\\\\\
\cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}
3 0
3 years ago
A rectangular box is 8 and a half inches long,5and a fourth inches wide,and 4 inches high.what is its volume
konstantin123 [22]
You multiply 8.5 by 5.25 by 4 and get 178.5 
7 0
3 years ago
Graph the line 2x + y = 7.
OLga [1]

Answer:f

Step-by-step explanation:

5 0
3 years ago
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· Hollywood Studios in Disneyworld is building a 2nd parking garage for The Muppets. The
Margarita [4]

Answer:

1264 and 632

Step-by-step explanation:

x + 2x = 1896

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5 0
3 years ago
Hello! Please Help Its just one simple Question ^^
Flura [38]

\\ \sf\longmapsto f(x)=112-kx

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Put -3 in f(x)

\\ \sf\longmapsto f(-3)=121

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\\ \sf\longmapsto 112+3k=121

\\ \sf\longmapsto 3k=9

\\ \sf\longmapsto k=3

4 0
3 years ago
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