<u>Answer:</u>
The cost of one gallon of gas in Toronto, Canada is $3.458.
<u>Solution:
</u>
Given, One gallon of gasoline in buffalo, New York costs $2.29.
In Toronto, Canada, one liter of gas costs $0.91.
There are 3.8 liters in one gallon.
We have to find how much does one gallon of gas cost in Toronto?
Now, cost of one gallon of gas in Toronto = cost of one litre of gas in Toronto x 3.8 liters for 1 gallon.
Cost of one gallon of gas = 0.91 x 3.8 = 3.458
Hence, the cost of one gallon of gas in Toronto, Canada is $3.458.
Place the part (amount going to the left field), over the total amount of homerun:
(a) 2/57 is your probability
(b) Divide 2/57
2/57 = 0.035, or 3.5%
YES, it is unusual for this player to hit a home run to left field, for he only has a 3.5% chance.
hope this helps
Here is an example:
Josh bought 7 apples for $21.
21/7 is 3, so one apple costs $3. This is the unit rate.
21/7 simplifies to 3/1, that’s another way to think about it. Simplify the fraction until the denominator is 1.
Hope this helps! Tell me if you have any questions!
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
Answer:
1. is 45/2
2. is 12/5
3. is 4/5
4. is 14
5. is 28
6. is 6 hope this helps :)
Step-by-step explanation:
