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musickatia [10]
3 years ago
14

In Mr.R class the ratio of the number girls to the number of boys is 3:2 A student is selected at random from the class The prob

ability that the selected student is a boy? (The answer choices are fractions)
Mathematics
1 answer:
Schach [20]3 years ago
4 0
3/5 are girls and 2/5 are boys

-> chance of 2/5 to select a boy randomly
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Multiply (2 -10i) (-5 + 3i) Show each step for credit!
jonny [76]

Answer:

The answer is

<h2>20 + 56i</h2>

Step-by-step explanation:

(2 -10i) (-5 + 3i)

Using FOIL multiply each term in the first bracket by the terms in the second <u>bracket</u>

That's

2(-5) + 2(3i) - 10i(-5) - 10i(3i)

<u>Multiply the numbers and simplify</u>

We have

- 10 + 6i + 50i - 30i²

From the rules of imaginary numbers

<h3>i² = - 1</h3>

So we have

- 10 + 56i - 30(- 1)

- 10 + 56i + 30

Simplify

30 - 10 + 56i

We have the final answer as

<h3>20 + 56i</h3>

Hope this helps you

5 0
3 years ago
An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609&#10;)+618

A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498&#10;

A(1.03)\approx 2431.31&#10;

Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

3 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
Can someone PLEASE help with this
Afina-wow [57]

Answer: 226.19

Step-by-step explanation:

5 0
2 years ago
I need help, with these two answers..
8090 [49]

download answer here

5 0
3 years ago
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