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musickatia [10]
3 years ago
14

In Mr.R class the ratio of the number girls to the number of boys is 3:2 A student is selected at random from the class The prob

ability that the selected student is a boy? (The answer choices are fractions)
Mathematics
1 answer:
Schach [20]3 years ago
4 0
3/5 are girls and 2/5 are boys

-> chance of 2/5 to select a boy randomly
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Y=-x+7
Allisa [31]
Question 1:
y=-x+7
y=2x-2

(-x+7)=2x-2
-x+7+x=2x-2+x
7=2x-2+x
7+2=2x-2+x+2
9=3x
9/3=3x/3
3=x

y=-x+7
y=-(3)+7
y=4

Question 2:
y-1=2x
y+2x=5

y-1=2x
y-1+1=2x+1
y=2x

(2x+1)+2x=5
2x+1+2x=5
4x+1=5
4x+1-1=5-1
4x=4
4x/4=4/4
x=1

y-1=2(1)
y-1+1=2+1
y=3

Answer: x=1 y=3

6 0
3 years ago
What is the measure of XYZ shown in the diagram below?
Crazy boy [7]

Answer: A.                                                                                                          

Explenation: Apex                                

4 0
3 years ago
Read 2 more answers
he closing price of a share of stock in Company XYZ is $25.69 on Thursday. If the change from the closing price on Wednesday is
mamaluj [8]

Answer:

Option C - $26.44

Step-by-step explanation:

To find the closing proce on Wednesday

Company XYZ is $ 25.69 on Thursday

Company XYZ is - $0.75 on Wednesday

This means the calculation should be as following,

25.69 + 0.75 = 26.44$ the closing price for Wednesday

6 0
3 years ago
An orange has about 1/4 cup of juice. How many oranges are needed to make 2 1/2 cups of juice? Select all equations that represe
san4es73 [151]
A and D are correct. To understand this, you need to know that this scenario gives us a total (2 1/2 cups) and a part (1/4). When you have these 2 pieces of information you have either a division problem with a total divided into parts (choice D) or you have one part and a totol shown as a multiplication problem (choice A).
7 0
3 years ago
Read 2 more answers
Select "Growth" or "Decay" to classify each function.
frozen [14]

y=c(a)^x\\\\if\ a > 0\ then\ "Growth"\\\\if\ 0 < a < 1\ then\ "Decay"\\-----------------------------\\y=200(0.5)^{2t}\to a=0.5 < 1-"Decay"\\\\y=\dfrac{1}{2}(2.5)^{\frac{t}{6}}\to a=2.5 > 1-"Growth"\\\\y=(0.65)^{\frac{t}{4}}\to a=0.65 < 1-"Decay"

5 0
3 years ago
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