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2 years ago

What is the area of this circle?

Mathematics

1 answer:

Juli2301 [7.4K]2 years ago

5 0

Answer:

The area will be 113.1

Step-by-step explanation:

hope it helps u

have a great day

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If the divisor is 4 and the quotient is 8, what is the dividend ?

kolbaska11 [484]

<h3>If the divisor is 4 and the quotient is 8, Then, dividend is 32</h3>

Solution:

Given that,

Divisor = 4

Quotient = 8

To find: dividend

We know that,

$Dividend \div divisor = quotient$

Therefore,

$Dividend \div 4 = 8\\\\Dividend \times \frac{1}{4} = 8\\\\Dividend = 8 \times 4\\\\Dividend = 32$

Thus, dividend is 32

3 0

2 years ago

QUESTÃO DE PL (PROGRAMAÇÃO LINEAR):

ra1l [238]

Essa pergunta nao esta em forma ingles, então pessoas nao vao entender.

3 0

2 years ago

What is the answer to this?

tensa zangetsu [6.8K]

The answer is b!!!!!

6 0

2 years ago

What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4

Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

$I = \frac{P}{4\pi d^{2}}$

where P: is the power ans d: is the distance.

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

$\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}$

where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km

$\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}$

$\frac{I_{1}}{I_{2}} = 5.9:1$

Therefore, the ratio of the intensities is roughly 6:1.

I hope it helps you!

3 0

2 years ago

Can someone help!!! ASAP

vekshin1

4/5 because look at the picture

6 0

3 years ago