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vichka [17]
3 years ago
5

¿Cual es el mínimo común múltiplo de 20 14 y 17? Gracias ♥ ♥

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

El mínimo común múltiplo de 20 14 y 17 es <u>1</u>.

17 es un número primo, y su únicos múltiplos son 17 y 1.

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Hi if someone can answer the top one I’ll mark u brainliest thanks
Kryger [21]

Answer:

the answer is a

Step-by-step explanation:

i got corrected :)

6 0
3 years ago
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using two of the number cards from the list, fill in the gaps so that the values are in ascending order
Mademuasel [1]

The two gaps of the series are 236 % and 2.41.

The series is 2(32/100) _, _ , 247/100.

We are given that the series is in ascending order.

Let the missing numbers be x and y respectively.

We know that  2(32/100) = 2.32 in decimal form and 247/100 is 2.47 in decimal form.

Hence, we can write,

2.32 < x < y < 2.47

The given options are:-

231 % = 231/100 = 2.31 < 2.32

Hence, it is not the answer.

0.42 < 2.31

Hence, it is not the answer.

236 % = 236/100 = 2.36 > 2.31

Hence, this is one of the answers.

34 % = 0.34

0.34 < 2.31

Hence, it is not the answer.

0.237 < 2.31

Hence, it is not the answer.

2.41 > 2.32

Hence, this is one of the answers.

24.2 % = 24.2/100 = 0.242 < 2.31

Hence, it is not the answer.

0.36 < 2.31

Hence, it is not the answer.

As, 2.36 < 2.41, hence,

x = 2.36 or 236 % and,

y = 2.41

To learn more about  series, here:-

brainly.com/question/15415793

#SPJ1

6 0
1 year ago
12/2 as a whole number or mixed number
bogdanovich [222]
It is a mixed number because 12/2 can be written as 6 instead of 12/2
4 0
2 years ago
Read 2 more answers
HELP ILL GIVE YOU BRAINLIEST!
kirza4 [7]

Answer:

Factoring

Step-by-step explanation:

6x^2+13x-5=0\\6x^2-2x+15x-5=0\\2x(3x-1)+5(3x-1)=0\\(2x+5)(3x-1)=0\\x=-\frac{5}{2},x=\frac{1}{3}

3 0
2 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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