Because the vertex of the parabola is at (16,0), its equation is of the formy = a(x-10)² + 15
The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].
It is the lateral edge as it is an edge and it is on the lateral area.
Answer:
I'm sorry I cant solve this without an X value but if you tell me the x value i'd be glad to help you out in the comment section below.
Step-by-step explanation:
Answer:
D. x=6
Step-by-step explanation:
-3x + 5= -2x -1
more variables to left hand side and change its sign
-3x+2x+5=-1
move constant to right hand side and change its sign
-3x+2x=-1-5
collect like terms
-x=-1-5
calculate the difference
-x=-6
change the signs on both sides of the equation
x=6