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DENIUS [597]
3 years ago
9

What is 1-4-x-(4-1)=-x-2-(4) With your work shown

Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0

Lets take this step by step.

1-4-x-(4-1)=-x-2-(4)

first, we'll simplify the parentheses on the left side of the equation.

1-4-x-3=-x-2-(4)

second, we'll combine like terms on the left side.

-6-x=-x-2-(4)

third, we'll combine like terms on the right side of the equation.

-6-x=-6-x

since these are equal, (x=x), we have infinitely many solutions.

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Hey What is -5t > 10
yanalaym [24]

Answer: 10 (ten) is an even number

following 9 and preceding 11

Step-by-step explanation:

3 0
2 years ago
Al sumar fracciones con igual denominador, debemos sumar numerador con numerador y denominador con denominador. Verdadero o fals
Ahat [919]

Answer:

La respuesta es falso.  

Step-by-step explanation:

La respuesta es falso.  

Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:    

\frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} = \frac{4}{5}

En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.

 

Por lo tanto, la respuesta es falso.

Espero que te sea de utilidad!

7 0
2 years ago
At the city museum, child admission is $5.80 and adult admission is $9.60. On Friday, three times as many adult tickets as child
noname [10]
Its 74 and if its wrong im sorry but hi
7 0
3 years ago
Two airplanes leave dallas at the same time and fly in opposite directions. One airplane travels 80 miles per hour faster then t
RSB [31]

recall d = rt, distance = rate * time.


let's say airplane A is going at a rate of "r", therefore airplane B is moving faster, at a rate of "r + 80".

now, after 3 hours, both planes have been travelling for 3 hours each, and say if A has covered "d" miles, then B has covered the slack of 2490 - d.


\bf \leftarrow \underset{A}{\stackrel{r}{\rule[0.22em]{8em}{0.25pt}}}dallas\underset{B}{\stackrel{r+80}{\rule[0.22em]{18em}{0.25pt}}}\to \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ plane~A&d&r&3\\ plane~B&2490-d&r+80&3 \end{array}


\bf \begin{cases} \boxed{d}=3r\\ 2490-d=(r+80)(3) \end{cases} \\\\\\ 2490-\boxed{3r}=3r+240\implies 2250=6r\implies \cfrac{2250}{6}=r\implies \stackrel{A}{375}=r \\\\\\ \stackrel{B}{375+80\implies 455}

4 0
3 years ago
Can you explain it please and which method is correct?​
Ksju [112]

Answer:

The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.

Step-by-step explanation:

Here's why each one did or didn't work:

First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.

Second answer- since you added the numerator separately and then did the basic division, this worked.

Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.

3 0
2 years ago
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