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3 years ago

Write down the nth term of this sequence 2,7,12,17,22

2 answers:

8 0

Adds 5 each times

an=a1+d(n-1)
a1=first term
d=common difference
n=which term

first term is 2
common diffference is 5 (7-2=5)

so
an=2+5(n-1)

the nth term is 2+5(n-1) or 5n-3

ki77a [65]3 years ago

6 0

There is a pattern. Each number is added by 5. So take 22 and add 5 to get 27. Just repeat until you find your answer, which would be 42.

You might be interested in

So when you are adding fractions how do you know when you need to simplify the numbers and how do you simplify?

rosijanka [135]

Let's look at an example.

We'll add the fractions 1/6 and 1/8

Before we can add, the denominators must be the same.

To get the denominators to be the same, we can...

multiply top and bottom of 1/6 by 8 to get 8/48
multiply top and bottom of 1/8 by 6 to get 6/48

At this point, both fractions involve the denominator 48. We can add the fractions like so

8/48 + 6/48 = (8+6)/48 = 14/48

Add the numerators while keeping the denominator the same the entire time.

The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.

14/2 = 7
48/2 = 24

The fraction 14/48 reduces to 7/24

Overall, 1/6 + 1/8 = 7/24

6 0

2 years ago

Manuel buys 7.9 pounds of strawberries. Each pound costs $3.89. Which expression gives the best estimate of the cost of the stra

topjm [15]

The options you gave are extremely confusing, but if you round 7.9 it is 8, and if you round $3.89 it is $4. Therefore, the best estimate would be 8•$4, or $32

7 0

3 years ago

Read 2 more answers

A sample of 10 adult elephants had an average weight of 12,556 pounds. The standard deviation

kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 3.25

The margin of error is:

M = T*s = 3.25*25 = 81

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

6 0

3 years ago

What is the answer? 8 x 4 + 9^2

Anuta_ua [19.1K]

8 x 4 is equal to 32 and 9^2 is 81. You add them together and get 113.

6 0

3 years ago

A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c

vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, $h_l$ , is given as follows;

$h_l$ = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0

3 years ago