onsider the binomial distribution with n trials and P(S) = p. (a) Show that p(y) p(y − 1) = (n − y + 1)p yq for y = 1, 2, , n. E
quivalently, for y = 1, 2, , n, the equation p(y) = (n − y + 1) p yq p(y − 1) gives a recursive relationship between the probabilities associated with successive values of Y.
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therefore the answer is 359.68$