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just olya [345]
3 years ago
12

Describe the relationship between x and y in a line with negative slope

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0
The value of y decreases as the value x increases
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PLEASE HELP KINGSSSS
creativ13 [48]

Answer:

30/52

Step-by-step explanation:

its a 26/52% chance to get a black card because 13 spain cards and 13 clovers add it together you get 26 and theirs 4 kings in a dack so add them both together 26/52+4/52=30/52

<h2>Answer: 30/52</h2>
3 0
2 years ago
Find the measure of the arc indicated
exis [7]

Answer:

Step-by-step explanation:

Angle GPE is an inscribed angle.  It intercepts arc GFE.  The rule for inscribed angles and the arcs they intercept is that the angle is half the measure of the arc it intercepts.  Angle P is 96, so that means that arc GFE is twice that.  2(96) = 192.  We have arc FG as 92, so that means that arc FE is 192 - 92 which is 100 degrees.  The third choice down.

4 0
2 years ago
URGENT. Find f(3) if<br> f(x)=x^3 + 2x^2-x-1
KonstantinChe [14]

Answer:

41

Step-by-step explanation:

Jus replace x with 3 and put it in a calculator.

6 0
3 years ago
Read 2 more answers
Derive the equation of the parabola with a focus at (0, −4) and a directrix of y = 4.
CaHeK987 [17]

<u>Answer:</u>

y=-\frac{1}{16} x^2

<u>Step-by-step explanation:</u>

Equation of parabola with focus at (0,-4) and directrix is y=4.

We know that parabola is the locus of all the points such that the distance from fixed point on the parabola to fixed line directrix is the same.

The parabola is opening downwards.

Let any point on parabola is (x,y).

Distance from focus(0,-4) to (x,y) = \sqrt{(x-0)^2+(y-(-4))^2}=|y-4|

\sqrt{(x-0)^2+(y-+4)^2}=|y-4|

(x-0)^2+(y+4)^2=(y-4)^2

(x)^2+(y+4)^2=(y-4)^2

x^2+(y^2+4y+4y+16)=y^2-4y-4y+16

x^2+y^2+8y+16=y^2-8y+16

x^2+16y^2=0

16y=-x^2

y=-\frac{1}{16} x^2

6 0
2 years ago
2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
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