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3 years ago

What is the range of the function y = 5sin(θ 60°) − 4?

1 answer:

4 0

he range if -5 ≤ y ≤ 5.

The period is 2π/(π/2) = 4.

The graph passes through (0, 0), has a maximum at (1, 5), crosses the x-axis at (2, 0), then has a minimum at (3. -5), and crosses the x-axis again at (4, 0).

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Solve for x: x + 15 = 45 Question 1 options: 30 60 -60 -30

brilliants [131]

Answer: A. 30. x=30/ 30=x *The answer should be the positive sign.*

Step-by-step explanation:

subtraction property of equality is subtracting the same number from both sides of an equation does not change the equation.

a-c=b-c

addition property of equality is adding the same number to both sides of an equation does not change the equation.

a+c=b+c

subtract by 15 both sides of an equation.

x+15-15=45-15

simplify.

45-15=30

30+15=45

45-30=15

x=30 and 30=x

Hope this helps!

Thanks!

Have a great day!

6 0

4 years ago

What is the value of y? Enter your answer, as an exact value, in the box. y =

bekas [8.4K]

Answer:

$y=2\sqrt{3}\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

$AC=BC$ -----> by a 45°-90°-45° triangle

$cos(45\°)=\frac{BC}{AB}$

$BC=ABcos(45\°)$

substitute the values

$BC=(2\sqrt{2})(\frac{\sqrt{2}}{2})=2\ units$

In the right triangle BCD

$tan(60\°)=\frac{BD}{BC}$

substitute the values

$\sqrt{3} =\frac{y}{2}\\ \\ y=2\sqrt{3}\ units$

4 0

4 years ago

Sketch the figure: Two different isosceles triangles with perimeter 4a + b

Nikitich [7]

The two triangles with the given perimeter is attached .

Perimeter is the sum of all sides.

For the first triangle , sies are 2a,2a and b.

So the perimeter is

$Perimeter = 2a+2a+b
\\
Perimeter = 4a+b$

For the second triangle, sides are a,a, and 2a+b. Therefore perimeter is

$Perimeter = a+ a + 2a+b
\\
Perimeter = 4a+b$

So for both triangles, perimeter is

$4a+b$

3 0

3 years ago

Can someone solve this equation and show the work please 8.3(x+3.1)=83

sp2606 [1]

This is the answer of the equation

3 0

3 years ago

a quarterback made 345 pass completions during one football season. if this was 60% of his attempts,how many passes did he attem

steposvetlana [31]

divide completions by percentage

345 / 0.60 = 575 pass attempts

4 0

3 years ago

Read 2 more answers