B. The statement is true because if the degree of the numerator of a rational function equals the degree of the denominator, then the rational function has a horizontal asymptote that is equal to the ratio of the leading coefficients.
The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer:
x = - 8, x = 6
Step-by-step explanation:
Given the 2 equations
x² + y² = 100 → (1)
y = x + 2 → (2)
Substitute y = x + 2 into (1)
x² + (x + 2)² = 100
x² + x² + 4x + 4 = 100
2x² + 4x + 4 = 100 ( subtract 100 from both sides )
2x² + 4x - 96 = 0 ( divide through by 2 )
x² + 2x - 48 = 0 ← in standard form
(x + 8)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 8 = 0 ⇒ x = - 8
x - 6 = 0 ⇒ x = 6
Answer:
The vehicle covers 126 miles on 7 gallons of fuel.
Step-by-step explanation:
Given:
The distance traveled is directly proportional to the amount of fuel.
For
gallons of fuel distance traveled
miles can be given as:
∝ ![F](https://tex.z-dn.net/?f=F)
![D=kF](https://tex.z-dn.net/?f=D%3DkF)
where
is constant of proportionality.
The vehicle covers
miles on
gallons.
So
![90=k(5)](https://tex.z-dn.net/?f=90%3Dk%285%29)
Dividing both sides by 5.
![\frac{90}{5}=\frac{k(5)}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B5%7D%3D%5Cfrac%7Bk%285%29%7D%7B5%7D)
![18=k](https://tex.z-dn.net/?f=18%3Dk)
∴ ![k=18](https://tex.z-dn.net/?f=k%3D18)
When
gallons
![D=(18)(7)](https://tex.z-dn.net/?f=D%3D%2818%29%287%29)
miles
∴ The vehicle covers 126 miles on 7 gallons of fuel.
We can write a proportion for this problem
10,000drops of a liquid is 10 fluid ounces
100 drops of a liquid is x fluid ounces
x=100*10/10000 =1/10 = 0.1 fluid ounces