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nika2105 [10]
4 years ago
11

Sarah earns $20 a day working after school. She spent 30% of her daily earnings on

Mathematics
2 answers:
Anarel [89]4 years ago
6 0

Answer:

6 Dallas

Step-by-step explanation:

30 percent of 20$ is 6$

30 percent *20 =

( 30:100)*20 =

( 30*20):100 =

600:100 = 6

Bogdan [553]4 years ago
6 0
The other answer is correct I checked
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write the equation of the ellipse using the given information: the ellipse has foci (0,3) and (0,-3) and major vertices (0,5) an
svetlana [45]

Answer: (x^2)/16 + (y^2)/25 = 1

Step-by-step explanation:

According to the problem we can figure out that the center of the ellipse is (0,0).

Since the foci is (0,3) and (0,-3) we know that the value of c is 3. The major vertices are (0,5) and (0,-5) so the value of a is 5.

If we put this into the equation a^2=b^2 + c^2, we get 25=9+ b^2

We get b^2 is 16

Now since we know that the ellipse is vertical because the x value didn’t change, we know that the b^2 value comes first in the equation. Then the a^2 value which is 25.

5 0
2 years ago
-27+9-3+1 using sigma notation
Vesna [10]
Do you have question choices if not then I'll try I guess...... -27+9-3+1 36-3+1 3
4 0
4 years ago
For each of the finite geometric series given below, indicate the number of terms in the sum and find the sum. For the value of
kotykmax [81]

Answer:

Number of term N = 9

Value of Sum = 0.186

Step-by-step explanation:

From the given information:

Number of term N = 3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} + \cdots + 3 (0.5)^{13}

Number of term N = 3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} +3 (0.5)^{8}+3 (0.5)^{9} +3 (0.5)^{10} +3 (0.5)^{11}+3 (0.5)^{12}+ 3 (0.5)^{13}

Number of term N = 9

The Value of the sum can be determined by using the expression for geometric series:

\sum \limits ^n_{k=m}ar^k =\dfrac{a(r^m-r^{n+1})}{1-r}

here;

m = 5

n = 9

r = 0.5

Then:

\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.5^5-0.5^{9+1})}{1-0.5}

\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.03125-0.5^{10})}{0.5}

\sum \limits ^n_{k=m}ar^k =\dfrac{(0.09375-9.765625*10^{-4})}{0.5}

\sum \limits ^n_{k=m}ar^k =0.186

6 0
3 years ago
ASAP PLS ANSWER HELP
castortr0y [4]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: Answer #1 in top left corner

Explanation:

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I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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4 0
3 years ago
Read 2 more answers
Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
djyliett [7]

Answer:

C) The third table. K= 5

C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
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