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3 years ago

Y decreased by 25 =10

2 answers:

8 0

Written in standard form, y decreased by 25 = 10 is y - 25 = 10

Now let's solve:

y - 25 = 10
y = 10 + 25
y = 35

to check:

35 - 25 = 10

so, y equals 35

RideAnS [48]3 years ago

7 0

Y is equal to 35. You do the opposite which is addition and add 25 and ten. Then you plug it in to make sure it's right.

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An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 390 feet of antiqu

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Twice as number decreased by 9 is 7

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4 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

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The function is defined for

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This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

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3 years ago

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OlgaM077 [116]

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Step-by-step explanation:

This is just an example.

If this helps please mark as brainliest

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