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3 years ago

How do I solve this equation?

Mathematics

2 answers:

AnnyKZ [126]3 years ago

4 0

Okay so basically all you do is first subtract 2 from 2 and from 17. positive minus a negative 2 cancels out. Once this is done, you simplify your answer to 5x<15. Then, you divide both sides by 5 to get the variable by itself. 5x divided by 5 cancels out to 1 and 15 divided by 5 equals 3. This means that you answer will be x<3 and being that you did not multiply or divide by any negatives, the inequality sign stays the same and doesn’t flip... I hope this helps

aalyn [17]3 years ago

3 0

Answer:

x< 3

Step-by-step explanation:

5x+2<17

-2. -2

5x<15

Divide both sides by 5

x< 3

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AURORKA [14]

Answer:

Step-by-step explanation:

Using the Cosine rule to find ∠ A

cosA = $\frac{b^2+c^2-a^2}{2bc}$

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m_a_m_a [10]

Given:

The equation is

$\dfrac{1}{3}x=\dfrac{1}{5}$

To find:

The coefficient and reciprocal.

Solution:

We have,

$\dfrac{1}{3}x=\dfrac{1}{5}$

Here, $\dfrac{1}{3}$ is multiplied with x.

So, the coefficient of x is $\dfrac{1}{3}$ .

To find the reciprocal, we need to interchange numerator and denominator of a fraction.

So, the reciprocal of $\dfrac{1}{3}$ is $\dfrac{3}{1}=3$

Therefore, the reciprocal is 3.

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3 years ago