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4 years ago

PLEASE HELP.BEST GETS BRAINLIEST.

1 answer:

7 0

-- Sum: the result of addition; (5x + 1)

-- Term: 5x or 3y .

-- Product: the result of multiplication; 5·x, 3·y, 9·(5x+1)

-- Factor: numbers that are multiplied;

   5 and 'x',    3 and 'y',    9 and (5x + 1)

-- Quotient: the result of division;    the whole expression is
      one big quotient; it's the
result of dividing 9(5x + 1) by 3y .

-- Coefficient: a number multiplied by a letter, or
   a letter multiplied by a number;

   5 is the coefficient of 'x'
      'x' is the coefficient of 5

3 is the coefficient of 'y'
   'y' is the coefficient of 3 .

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Which equation is represented by the table?

Fantom [35]

The answer is C.

(0, 3)

y = x + 3

3 = 0 + 3

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y = x + 3

4 = 1 + 3

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(2, 5)

y = x + 3

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6 0

3 years ago

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Solve the inequality |2x|+7>15

Radda [10]

<span>|2x|+7>15 Set it to 0 and remove absolute value bars
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7 0

4 years ago

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The first two classes of a frequency distribution are 0-9 and 10-19. What is the class width?

likoan [24]

Answer: (a) 9

Step-by-step explanation:

We are given that ,

The first two classes of a frequency distribution are 0-9 and 10-19.

We know that the class width of an class interval is basically the difference between the upper limit and the lower limit of the interval.

For example the class interval for interval 40 - 45 is 5 because 45-40=5.

For the given class interval 0-9 , upper limit= 9

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⇒ Class width = 9-0= 9

Similarly , for 10-19 , the class width = 19-10=9

Therefore , the class width is 9 .

Hence, the correct answer is (a) 9.

4 0

3 years ago

Solve the equation 2^(2x+1)+8=17×2^x.

myrzilka [38]

Oooh, looks fun

ok
erm
we might want to know some properties
$(x^m)(x^n)=x^{m+n}$
$(a^b)^c=a^{bc}$
if $a^m=a^n$ where a=a, then assume m=n

$2^{2x+1}=(2^{2x})(2^1)$
so
$(2^{2x})(2)+8=17(2^x)$
$(2^{2x})(2)+2^3=17(2^x)$
$(2^x)^2(2)+2^3=17(2^x)$
minus 17*2^x both sides
$(2^x)^2(2)+2^3-17(2^x)=0$
use u subsitution, u=2ˣ
$(u)^2(2)+2^3-17(u)=0$
solve $2u^2+8-17u=0$
or
$2u^2-17u+8=0$
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
$2^3=2^x$
3=x

and
$\frac{1}{2}=2^x$
$2^{-1}=2^x$
-1=x

x=-1 and 3
neat problem

8 0

3 years ago

PLS HELP ME!!!!!!!!! WILL MARK BRAINLIEST!!!!!

Bas_tet [7]

Answer:

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Step-by-step explanation:

8 0

3 years ago

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