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stich3 [128]
3 years ago
14

Carla can choose two of her three pairs of sneakers to take to a track meet. If the pairs of sneakers are called A, B, and C, wh

ich choice represents the sample space, S, for the event? S = {ABC} S = {ABC, CAB} S = {AB, AC, BC} S = {AB, BA, AC, CA, BC, CB}
Mathematics
2 answers:
Semenov [28]3 years ago
5 0
Number of ways of choosing two pair of sneakers from three pairs named A, B, C is given by 3C2 (3 combination 2) = 3! / 2!(3 - 2)! = 3! / (2! x 1!) = (3 x 2) / (2 x 1) = 3.

Therefore, the sample space is given by S = {AB, AC, BC}
Nuetrik [128]3 years ago
3 0
Its the third one hope this helps!!!!!!!!!
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At a certain time of day, a tree that is x meters tall casts a shadow that is x−46x−46 meters long. if the distance from the top
Alexus [3.1K]
By the Pythagorean theorem,
.. x^2 +(x -46)^2 = (x +4)^2
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.. (x -50)^2 -400 = 0
.. x = 50 ±20 . . . . . only x=70 makes any sense in the problem

The height, x, of the tree is 70 meters.
5 0
3 years ago
Find the product. Simplify your answer x^2-y^2/6*12/x-y
Ratling [72]
= x^2 - y^2/6 * 12/(x-y)
= 6x^2 -y^2 * 72/(x-y)
= 6x^2(x-y) -y^2(x-y) * 72
= 6x^3 - 18x^2 -xy^2 + y^3 * 72
= 432x^3 - 1296x^2 -72xy^2 + 72y^3 
5 0
3 years ago
What is the answer ?
adell [148]

The most reasonable would be grams.

5 0
3 years ago
Read 2 more answers
Operations with fractions
romanna [79]
The asnwer is 2/8 (simplified it would be 1/4)
5 0
2 years ago
Read 2 more answers
Which function has an average rate of change of -4 over the interval [-2,2]?
kolbaska11 [484]

Only p(x) has an average rate of change of -4 over [-2, 2].

Find the average rate of change of each given function over the interval [-2, 2]]:

The average rate of change of m(x) over [-2, 2]:

<h3>What is the average rate?</h3>

The average rate of change = \frac{m(b)-m(a)}{b-a}

Where, a = -2, m(a) = -12

b = 2, m(b) = 4

Plug the values into the equation

The average rate of change

=\frac{4-(-12)}{2-(-2)} =\frac{16}{4}

The average rate of change = 4

The average rate of change of n(x) over [-2, 2]:

The average rate of change = \frac{n(b)-n(a)}{b-a}

Where, a = -2, n(a) = -6

b = 2, n(b) = 6

Plug the values into the equation

The average rate of change

=\frac{6-(-6)}{2-(-2)} \\=\frac{12}{4}

The average rate of change = 3

The average rate of change of q(x) over [-2, 2]:

The average rate of change = \frac{q(b)-q(a)}{b-a}

Where, a = -2, q(a) = -4

b = 2, q(b) = -12

Plug the values into the

The average rate of change = \frac{-4-12}{2-(-2)}

= \frac{-16}{4}

The average rate of change = -2

The average rate of change of p(x) over [-2, 2]:

The average rate of change = \frac{p(b)-p(a)}{b-a}

Where, a = -2, p(a) = 12

b = 2, p(b) = -4

Plug the values into the equation

The average rate of change = \frac{-4-12}{2-(-2)}

=\frac{-16}{4}

The average rate of change = -4

The answer is D.

Only p(x) has an average rate of change of -4 over [-2, 2].

To learn more about the average rate of visit:

brainly.com/question/8728504

#SPJ1

8 0
1 year ago
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