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2 years ago

(1.7)(1.7) what does this equal

Mathematics

1 answer:

givi [52]2 years ago

3 0

The answer to that is 2.89

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Please help and show work if you can

laila [671]

Answer:

25. a = 60

26. a = 17

Step-by-step explanation:

In these two problems we are going to use a property of parallelograms that says: opposite angles have equal measure

so we have

25.

$6a+10=130\\\\6a=130-10\\\\6a=120\\\\a=60$

and for 26 we have

$4a-4=2a+30\\\\4a=2a+30+4\\\\4a=2a+34\\\\4a-2a=34\\\\2a=34\\\\a=17$

6 0

2 years ago

Find the area of the trapezoid.

butalik [34]

Answer:

8 ft

Step-by-step explanation:

t = a + b/2 times 2

2 + 6 = 8

8/2 = 4

4 x 2 = 8

8 0

2 years ago

In January, Angelina made one deposit of $90 to her savings account and made 3 withdrawals of $40 each. What was the total chang

Anna71 [15]

So 90 - (40*3) right ?

5 0

3 years ago

Read 2 more answers

The equation tan(55) = 15/b can be used to find the length of line AC.what is the length of line AC round to the nearest 10th 3.

Nadusha1986 [10]

Answer:

10.5 in

Step-by-step explanation:

Given

$tan(55) = \frac{15}{b}$

Required

Find length AC

The question is not detailed enough; so, I'll assume that b represents line AC.

Having said that;

We start by multiplying both sides by b

$tan(55) = \frac{15}{b}$

$b * tan(55) = \frac{15}{b} * b$

$b * tan(55) =15$

Divide both sides by tan(55)

$\frac{b * tan(55)}{tan(55)} = \frac{15}{tan(55)}$

$b = \frac{15}{tan(55)}$

Find tan(55)

$b = \frac{15}{1.42814800674}$

$b = 10.5031130731$

$b = 10.5$ <em>(Approximated)</em>

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Length AC is 10.5

7 0

3 years ago

Read 2 more answers

On paper, make a rectangle that has points A and B as two of its vertices and has a perimeter of 40 units. Draw and label the tw

Westkost [7]

Answer:

$A(x,y),B(x+10,y),C(x+10,y-10) \:and\: D(x,y-10)$

Step-by-step explanation:

If a Rectangle has a perimeter of 40 units, then we can write that formula and find the a formula for the coordinates:

$\left\{\begin{matrix}w+l=20 & \\ w*l=100 & \end{matrix}\right.\Rightarrow w=20-l\Rightarrow (20-l)l=100\Rightarrow -l^2+20l-100=0\Rightarrow l^2-20l+100\Rightarrow (l-10)(l-10)\Rightarrow l=10\therefore l=10\: and\: w=10$

Therefore we can say:

$A(x,y),B(x+10,y),C(x+10,y-10) \:and\: D(x,y-10)$

Technically when $w=l$ in this rectangle is a square, a degenerate square.

8 0

2 years ago