Let x equal the number of adult tickets sold.
X + 3X=512
(I put 3x because we know the students sold 3 times as many).
Solve for X.
X+3X=512
4X=512
4X/4=512/4
X=128
SO we need 5 numbers that equal to 20, with 5 being the middle number, and ones being the most used number so
1 1 5 x y
According to this, x and y must equal 13 and both be bigger then 5. Because we can rule out every other number, x and y must be 6 and 7.
Your 5 numbers are 1, 1, 5, 6, 7.
9(3j-6) = 27j - 54
<span>Note: a(b-c) = ab - ac</span>
A. 7.5 pages per hour B. $2.66 for one page
Answer:
law of cosines states c^2=a^2+b^2-2abc
b^2=26^2+24^2-2(26×24)cos 134°
b^2=676+576-1248cos134°
cos134= -0.6946
b^2=1252-12(-0.6946)
12×(-0.6946)= -8.3352
b^2=1252-(-8.3352)
b^2=1252+8.3352
b^2=1260.33
b=√1260.33
b=35.50
