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irakobra [83]
4 years ago
12

Please help!!! Given: △ABC is isosceles; 1 ≅ 3 Prove: AB || CD

Mathematics
1 answer:
chubhunter [2.5K]4 years ago
5 0

Answer:

Step-by-step explanation:

△ABC is isosceles. So ∠3 = ∠4

given 1 ≅ 3.

therefore, 1 ≅ 4

alternate interior angles are equal if only AB//CD

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A population has 75 observations. One class interval has a frequency of 15 observations. The relative frequency in this category
vovangra [49]

Answer:

The relative frequency in this category is 0.2

Step-by-step explanation:

The relative fraquency of a category is given by the number of observations in this category divided by the total number of observations.

In this question:

The category of interest has 15 observations.

In total, the population has 75 observations.

So the relative frequency is:

\frac{15}{75} = \frac{1}{5} = 0.2

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3 years ago
What's is 9 + 10 equal?
yanalaym [24]
9+10=19
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If a convex polyhedron has 12 edges and 8 faces, then how many vertices does it have?
Vika [28.1K]
Hi 

Use Euler's formula for this for a 3D figure. F + V = E + 2, where F is the number of faces, V is the number of vertices, E is the number of edges, +2! You have enough info to fill in the formula to find that the number of vertices is 6.
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4 years ago
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A closed-top cylindrical container is to have a volume of 250 in2. 250 , in squared , . What dimensions (radius and height) will
miv72 [106K]

Answer:

radius r = 3.414 in

height h = 6.8275 in

Step-by-step explanation:

From the information given:

The volume V of a closed cylindrical container with its surface area can be expressed as follows:

V = \pi r^2 h

S = 2 \pi rh + 2 \pi r^2

Given that Volume V = 250 in²

Then;

\pi r^2h = 250  \\ \\ h = \dfrac{250}{\pi r^2}

We also know that the cylinder contains top and bottom circle and the area is equal to πr²,

Hence, if we incorporate these areas in the total area of the cylinder.

Then;

S = 2\pi r h + 2 \pi r ^2

S = 2\pi r (\dfrac{250}{\pi r^2}) + 2 \pi r ^2

S = \dfrac{500}{r} + 2 \pi r ^2

To find the minimum by determining the radius at which the surface by using the first-order derivative.

S' = 0

- \dfrac{500}{r^2} + 4 \pi r = 0

r^3 = \dfrac{500 }{4 \pi}

r^3 = 39.789

r =\sqrt[3]{39.789}

r = 3.414 in

Using the second-order derivative of S to determine the area is maximum or minimum at the radius, we have:

S'' = - \dfrac{500(-2)}{r^3}+ 4 \pi

S'' =  \dfrac{1000}{r^3}+ 4 \pi

Thus, the minimum surface area will be used because the second-derivative shows that the area function is higher than zero.

Thus, from h = \dfrac{250}{\pi r^2}

h = \dfrac{250}{\pi (3.414) ^2}

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3 part question
eimsori [14]

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^62 with a numertor of 66 you divide by .21

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