<span>The solution is:
x(t) = 3*t^2 - 0.130*t^3
v(t) = x'(t) = 6*t - 0.360*t^2
v(5) = 6*5 - 0.360*5^2 = 21 m/s
v(10) = 6*10 - 0.360*10^2 = 24 m/s
set v(t) = 0 and solve for t
0 = 6*t - 0.360t^2
0 = t*(6-0.360*t)
6-0.360*t = 0
t = 6/.360 = 16.7 s</span>
Answer:
if the 1/4 was outside the parentheses then it would be a vertical compression. So it has to be a horizontal compression
Answer:
The sample should be as large as 480
Step-by-step explanation:
Probability of having a flu, p = 43/334
p = 0.129
Margin Error, E = 0.03
Confidence Interval, CI= 95%
At a CI of 95%,
The sample size can be given by the relation:
Answer:
7 sheets
Step-by-step explanation:
Dimension of gabble = 42' by 5'
Dimension of standard plywood sheet : 4' by 8'
Area that will be covered by gabble :
Length * width :
42 * 5 = 210 in²
Area covered by 1 plywood sheet :
4 * 8 = 32 in²
Number of plywood sheets required :
Area of gabble / Area of 1 plywood sheet
210 in² / 32 in²
= 6.5625
This means the number of plywood sheets that will be required is 7