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2 years ago

What is 25quarter and 3 nickels and 1pennie represent in decimal form and fraction form?

1 answer:

3 0

4 quarters is a dollar. So 25 divided by 4 is $6.25. A nickel is 5 cents, so multiply 3 by 5. Giving us $.15. And finally the one penny adds $.01. Add it all together and you get $6.41 for the decimal. Now for the fraction, since 100 cents is $1, the denominator is 100. And since there are $6, it would be 6_41/100 for the fraction.

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An object falls 9 meters during the first second, another 27 meters during the second second, and then 81 meters more during the

marishachu [46]

360 meters is the answer as 9 meter in 1st second ,27 meter in 2nd and 81 in 3rd it is in a series of geometric progression ...of 9,27,81 in which 9*3 =27,27*3=81 so next number will be 81*3=243 total distance moved in 4 seconds is 243+81+27+9=360 meters

4 0

3 years ago

Algebra 1 plz help me

sasho [114]

Answer:

Step-by-step explanation:

solution is (4,3)

x=4

y=3

this point lies in both the tables.

we have to find a pair which lies on both.

8 0

2 years ago

For each of the following vector fields F, decide whether it is conservative or not by computing curl F. Type in a potential fun

Burka [1]

Answer:

1,2 and 4 are conservatives

3 is not conservative

Step-by-step explanation:

We calculate the Curl F

Remember that:

Curl F = < $\frac{dFz}{dy} - \frac{dFy}{dz}, \frac{dFz}{dx} - \frac{dFx}{dz}, \frac{dFy}{dx} - \frac{dFx}{dy}$ >

1. Curl F = <0,0,5-5> = <0,0,0>

The potential function f so that ∇f=F

f(x,y,z) = $-3x^{2} +5xy + 5y^{2}$

Then F is conservative

2. Curl F = < 0, 0 ,0>

The potential function f so that ∇f=F

f(x,y,z) = $-3/2x^{2} -y^{2}+z$

Then F is conservative

3. Curl F = <0 ,0, 10+3xsin(y) - (-cos(y))>

= <0 ,0 , 10 +3xsin(y) + cos(y)<

How the field's divergence is not zero the vector field is not conservative

4. Curl F = <0, 0, 0>

The potential function f so that ∇f=F

f(x,y,z) = $x^{3}+(5/3)y^{3}+(5/3)z^{3}$

Then F is conservative

5 0

2 years ago

Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,

qaws [65]

$\dfrac{\partial f}{\partial x}=y^2z+2xz^2$
$f(x,y,z)=xy^2z+x^2z^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz$
$\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z$
$\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0$

$\implies f(x,y,z)=xy^2z+x^2z^2+C$

8 0

3 years ago

I need help with finding slopes from two points thank you

otez555 [7]

Answer:

i do believe the answer is 6/7

7 0

3 years ago